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Top View of a Binary Tree

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Top View of a Binary Tree

Top View of a Binary Tree is simple if you keep it on paper. Amit uses it for folder on disk in a file explorer.

Keep Top View of a Binary Tree small. Amit should finish folder on disk in a few lines, not a 40-line dump.

Top View of a Binary Tree exists so Amit can keep folder on disk correct in a file explorer.

Use Top View of a Binary Tree when folder on disk must stay clear. If a simpler DSA step works, use that instead.

If folder on disk breaks under Top View of a Binary Tree, check unbalanced BST becoming a list first.

Top View of a Binary Tree is not a lonely heading. Amit ties it to folder on disk.

One breath for Top View of a Binary Tree, then folder on disk, then unbalanced BST becoming a list. Sit down.

Exam tip

For Top View of a Binary Tree: definition + a file explorer + one failure.

Example

class Node:
    def __init__(self, val, left=None, right=None):
        self.val, self.left, self.right = val, left, right

def inorder(n):
    if not n:
        return []
    return inorder(n.left) + [n.val] + inorder(n.right)

root = Node(2, Node(1), Node(3))
print(inorder(root))

Top View of a Binary Tree — inorder walks left → node → right (sorted order for a BST).

Short notes

DefTop View of a Binary Tree — Amit uses it for folder on disk in a file explorer.
RuleTop View of a Binary Tree → left < root < right.
RememberTop View of a Binary Tree + time vs memory (a file explorer).
UseTop View of a Binary Tree in a file explorer (folder on disk).
TrapTop View of a Binary Tree — unbalanced BST becoming a list.
ExTop View of a Binary Tree → folder on disk.

class Node: def __init__(self, val, left=None, right=None): self.val, self.left, self.right = val, left, right def inorder(n): if not n: return [] return inorder(n.left) + [n.val] + inorder(n.right) root = Node(2, Node(1), Node(3)) print(inorder(root))

Top View of a Binary Tree

Example

Short notes

Questions

Top View of a Binary Tree

Example

Short notes

Questions