DSA · Theory

Serialize and Deserialize a Binary Tree

Theory

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Serialize and Deserialize a Binary Tree

Serialize and Deserialize a Binary Tree is simple if you keep it on paper. Ananya uses it for folder on disk in a file explorer.

Do Serialize and Deserialize a Binary Tree once by hand. left < root < right. Change one input. Say the new result out loud.

Skip Serialize and Deserialize a Binary Tree and unbalanced BST becoming a list shows up in a file explorer.

Use Serialize and Deserialize a Binary Tree when folder on disk must stay clear. If a simpler DSA step works, use that instead.

Serialize and Deserialize a Binary Tree trap: unbalanced BST becoming a list. Ananya loses marks for that every viva.

Serialize and Deserialize a Binary Tree is not a lonely heading. Ananya ties it to folder on disk.

Close Serialize and Deserialize a Binary Tree with: “If I skip it, folder on disk goes wrong like this: unbalanced BST becoming a list.”

Exam tip

Board: folder on disk. Dry-run Serialize and Deserialize a Binary Tree. Name the trap: unbalanced BST becoming a list.

Example

class Node:
    def __init__(self, val, left=None, right=None):
        self.val, self.left, self.right = val, left, right

def inorder(n):
    if not n:
        return []
    return inorder(n.left) + [n.val] + inorder(n.right)

root = Node(2, Node(1), Node(3))
print(inorder(root))

Serialize and Deserialize a Binary Tree — inorder walks left → node → right (sorted order for a BST).

Short notes

DefSerialize and Deserialize a Binary Tree — Ananya uses it for folder on disk in a file explorer.
RuleSerialize and Deserialize a Binary Tree → left < root < right.
RememberSerialize and Deserialize a Binary Tree + a dry-run table (a file explorer).
UseSerialize and Deserialize a Binary Tree in a file explorer (folder on disk).
TrapSerialize and Deserialize a Binary Tree — unbalanced BST becoming a list.
ExSerialize and Deserialize a Binary Tree → folder on disk.

class Node: def __init__(self, val, left=None, right=None): self.val, self.left, self.right = val, left, right def inorder(n): if not n: return [] return inorder(n.left) + [n.val] + inorder(n.right) root = Node(2, Node(1), Node(3)) print(inorder(root))

Serialize and Deserialize a Binary Tree

Example

Short notes

Questions

Serialize and Deserialize a Binary Tree

Example

Short notes

Questions