DSA · Theory

Get the Level of a Given Key in a Binary Tree

Theory

307/810

Get the Level of a Given Key in a Binary Tree

Get the Level of a Given Key in a Binary Tree sits in a file explorer. Kabir’s job is folder on disk. Write that first.

Get the Level of a Given Key in a Binary Tree order: meaning → left < root < right → one limit. Dumping ten features helps nobody.

Get the Level of a Given Key in a Binary Tree exists so Kabir can keep folder on disk correct in a file explorer.

Get the Level of a Given Key in a Binary Tree shows up in a file explorer. Name folder on disk, not “a real-world scenario”.

Get the Level of a Given Key in a Binary Tree miss: unbalanced BST becoming a list. Fix it before you talk about advanced DSA.

Get the Level of a Given Key in a Binary Tree is not a lonely heading. Kabir ties it to folder on disk.

Viva for Get the Level of a Given Key in a Binary Tree: what it is → left < root < right → the mistake (unbalanced BST becoming a list).

Exam tip

Say Get the Level of a Given Key in a Binary Tree in one breath, then left < root < right, then unbalanced BST becoming a list.

Example

class Node:
    def __init__(self, val, left=None, right=None):
        self.val, self.left, self.right = val, left, right

def inorder(n):
    if not n:
        return []
    return inorder(n.left) + [n.val] + inorder(n.right)

root = Node(2, Node(1), Node(3))
print(inorder(root))

Get the Level of a Given Key in a Binary Tree — inorder walks left → node → right (sorted order for a BST).

Short notes

DefGet the Level of a Given Key in a Binary Tree — Kabir uses it for folder on disk in a file explorer.
RuleGet the Level of a Given Key in a Binary Tree → left < root < right.
RememberGet the Level of a Given Key in a Binary Tree + a dry-run table (a file explorer).
UseGet the Level of a Given Key in a Binary Tree in a file explorer (folder on disk).
TrapGet the Level of a Given Key in a Binary Tree — unbalanced BST becoming a list.
ExGet the Level of a Given Key in a Binary Tree → folder on disk.

class Node: def __init__(self, val, left=None, right=None): self.val, self.left, self.right = val, left, right def inorder(n): if not n: return [] return inorder(n.left) + [n.val] + inorder(n.right) root = Node(2, Node(1), Node(3)) print(inorder(root))

Get the Level of a Given Key in a Binary Tree

Example

Short notes

Questions

Get the Level of a Given Key in a Binary Tree

Example

Short notes

Questions