DSA · Theory

Find Next Greater Element in Binary Tree

Theory

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Find Next Greater Element in Binary Tree

Don’t start Find Next Greater Element in Binary Tree with jargon. Start with folder on disk. That is the whole point.

Find Next Greater Element in Binary Tree on the board: left < root < right. Then say what folder on disk looks like after.

Find Next Greater Element in Binary Tree exists so Riya can keep folder on disk correct in a file explorer.

Riya ships Find Next Greater Element in Binary Tree in a file explorer. That is the use case worth saying.

Find Next Greater Element in Binary Tree miss: unbalanced BST becoming a list. Fix it before you talk about advanced DSA.

Find Next Greater Element in Binary Tree is not a lonely heading. Riya ties it to folder on disk.

Viva for Find Next Greater Element in Binary Tree: what it is → left < root < right → the mistake (unbalanced BST becoming a list).

Exam tip

For Find Next Greater Element in Binary Tree: definition + a file explorer + one failure.

Example

class Node:
    def __init__(self, val, left=None, right=None):
        self.val, self.left, self.right = val, left, right

def inorder(n):
    if not n:
        return []
    return inorder(n.left) + [n.val] + inorder(n.right)

root = Node(2, Node(1), Node(3))
print(inorder(root))

Find Next Greater Element in Binary Tree — inorder walks left → node → right (sorted order for a BST).

Short notes

DefFind Next Greater Element in Binary Tree — Riya uses it for folder on disk in a file explorer.
RuleFind Next Greater Element in Binary Tree → left < root < right.
RememberFind Next Greater Element in Binary Tree + Big-O (a file explorer).
UseFind Next Greater Element in Binary Tree in a file explorer (folder on disk).
TrapFind Next Greater Element in Binary Tree — unbalanced BST becoming a list.
ExFind Next Greater Element in Binary Tree → folder on disk.

class Node: def __init__(self, val, left=None, right=None): self.val, self.left, self.right = val, left, right def inorder(n): if not n: return [] return inorder(n.left) + [n.val] + inorder(n.right) root = Node(2, Node(1), Node(3)) print(inorder(root))

Find Next Greater Element in Binary Tree

Example

Short notes

Questions

Find Next Greater Element in Binary Tree

Example

Short notes

Questions