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Construct a linked list from a 2D Matrix

Theory

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Construct a linked list from a 2D Matrix

Isha only reaches for Construct a linked list from a 2D Matrix when a ticket queue node has to stay correct in a counter.

For Construct a linked list from a 2D Matrix, a dry-run table is in play. Don’t blame it until you have traced a ticket queue node.

Skip Construct a linked list from a 2D Matrix and losing the next pointer on delete shows up in a counter.

Use Construct a linked list from a 2D Matrix when a ticket queue node must stay clear. If a simpler DSA step works, use that instead.

If a ticket queue node breaks under Construct a linked list from a 2D Matrix, check losing the next pointer on delete first.

Construct a linked list from a 2D Matrix is not a lonely heading. Isha ties it to a ticket queue node.

Viva for Construct a linked list from a 2D Matrix: what it is → head → next → … → the mistake (losing the next pointer on delete).

Diagram

  [10] → [20] → [30] → /
   head              tail

Exam tip

Say Construct a linked list from a 2D Matrix in one breath, then head → next → …, then losing the next pointer on delete.

Example

class Node:
    def __init__(self, val, next=None):
        self.val = val
        self.next = next

head = Node(1, Node(2, Node(3)))
cur = head
while cur:
    print(cur.val, end=" -> " if cur.next else "\n")
    cur = cur.next

Construct a linked list from a 2D Matrix — a linked list chains nodes with next pointers instead of contiguous indexes.

Short notes

DefConstruct a linked list from a 2D Matrix — Isha uses it for a ticket queue node in a counter.
RuleConstruct a linked list from a 2D Matrix → head → next → ….
RememberConstruct a linked list from a 2D Matrix + a dry-run table (a counter).
UseConstruct a linked list from a 2D Matrix in a counter (a ticket queue node).
TrapConstruct a linked list from a 2D Matrix — losing the next pointer on delete.
ExConstruct a linked list from a 2D Matrix → a ticket queue node.

class Node: def __init__(self, val, next=None): self.val = val self.next = next head = Node(1, Node(2, Node(3))) cur = head while cur: print(cur.val, end=" -> " if cur.next else "\n") cur = cur.next

Construct a linked list from a 2D Matrix

Example

Short notes

Questions

Construct a linked list from a 2D Matrix

Example

Short notes

Questions