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Cartesian tree from inorder traversal

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Cartesian tree from inorder traversal

Cartesian tree from inorder traversal sits in a file explorer. Neha’s job is folder on disk. Write that first.

Keep Cartesian tree from inorder traversal small. Neha should finish folder on disk in a few lines, not a 40-line dump.

Cartesian tree from inorder traversal exists so Neha can keep folder on disk correct in a file explorer.

Use Cartesian tree from inorder traversal when folder on disk must stay clear. If a simpler DSA step works, use that instead.

Cartesian tree from inorder traversal trap: unbalanced BST becoming a list. Neha loses marks for that every viva.

Cartesian tree from inorder traversal is not a lonely heading. Neha ties it to folder on disk.

One breath for Cartesian tree from inorder traversal, then folder on disk, then unbalanced BST becoming a list. Sit down.

Exam tip

Board: folder on disk. Dry-run Cartesian tree from inorder traversal. Name the trap: unbalanced BST becoming a list.

Example

class Node:
    def __init__(self, val, left=None, right=None):
        self.val, self.left, self.right = val, left, right

def inorder(n):
    if not n:
        return []
    return inorder(n.left) + [n.val] + inorder(n.right)

root = Node(2, Node(1), Node(3))
print(inorder(root))

Cartesian tree from inorder traversal — inorder walks left → node → right (sorted order for a BST).

Short notes

DefCartesian tree from inorder traversal — Neha uses it for folder on disk in a file explorer.
RuleCartesian tree from inorder traversal → left < root < right.
RememberCartesian tree from inorder traversal + Big-O (a file explorer).
UseCartesian tree from inorder traversal in a file explorer (folder on disk).
TrapCartesian tree from inorder traversal — unbalanced BST becoming a list.
ExCartesian tree from inorder traversal → folder on disk.

class Node: def __init__(self, val, left=None, right=None): self.val, self.left, self.right = val, left, right def inorder(n): if not n: return [] return inorder(n.left) + [n.val] + inorder(n.right) root = Node(2, Node(1), Node(3)) print(inorder(root))

Cartesian tree from inorder traversal

Example

Short notes

Questions

Cartesian tree from inorder traversal

Example

Short notes

Questions