DSA · Theory

Burn the Binary tree from the Target node

Theory

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Burn the Binary tree from the Target node

Priya only reaches for Burn the Binary tree from the Target node when folder on disk has to stay correct in a file explorer.

Burn the Binary tree from the Target node on the board: left < root < right. Then say what folder on disk looks like after.

Skip Burn the Binary tree from the Target node and unbalanced BST becoming a list shows up in a file explorer.

Use Burn the Binary tree from the Target node when folder on disk must stay clear. If a simpler DSA step works, use that instead.

Burn the Binary tree from the Target node miss: unbalanced BST becoming a list. Fix it before you talk about advanced DSA.

Burn the Binary tree from the Target node is not a lonely heading. Priya ties it to folder on disk.

One breath for Burn the Binary tree from the Target node, then folder on disk, then unbalanced BST becoming a list. Sit down.

Exam tip

Board: folder on disk. Dry-run Burn the Binary tree from the Target node. Name the trap: unbalanced BST becoming a list.

Example

class Node:
    def __init__(self, val, left=None, right=None):
        self.val, self.left, self.right = val, left, right

def inorder(n):
    if not n:
        return []
    return inorder(n.left) + [n.val] + inorder(n.right)

root = Node(2, Node(1), Node(3))
print(inorder(root))

Burn the Binary tree from the Target node — inorder walks left → node → right (sorted order for a BST).

Short notes

DefBurn the Binary tree from the Target node — Priya uses it for folder on disk in a file explorer.
RuleBurn the Binary tree from the Target node → left < root < right.
RememberBurn the Binary tree from the Target node + time vs memory (a file explorer).
UseBurn the Binary tree from the Target node in a file explorer (folder on disk).
TrapBurn the Binary tree from the Target node — unbalanced BST becoming a list.
ExBurn the Binary tree from the Target node → folder on disk.

class Node: def __init__(self, val, left=None, right=None): self.val, self.left, self.right = val, left, right def inorder(n): if not n: return [] return inorder(n.left) + [n.val] + inorder(n.right) root = Node(2, Node(1), Node(3)) print(inorder(root))

Burn the Binary tree from the Target node

Example

Short notes

Questions

Burn the Binary tree from the Target node

Example

Short notes

Questions